360-12x-4x^2=0

Solution for 360-12x-4x^2=0 equation:

360-12x-4x^2=0

a = -4; b = -12; c = +360;
Δ = b2-4ac
Δ = -122-4·(-4)·360
Δ = 5904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5904}=\sqrt{144*41}=\sqrt{144}*\sqrt{41}=12\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{41}}{2*-4}=\frac{12-12\sqrt{41}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{41}}{2*-4}=\frac{12+12\sqrt{41}}{-8}
$